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Post by tickingmask on Apr 14, 2023 7:46:38 GMT
Back by popular demand! Sorry the image is a bit small.
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Post by Jep Gambardella on Apr 14, 2023 16:49:32 GMT
I am assuming that the two internal lines don't necessarily end in the exact middle of the left and right sides of the larger triangle?
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Post by tickingmask on Apr 14, 2023 17:46:08 GMT
I am assuming that the two internal lines don't necessarily end in the exact middle of the left and right sides of the larger triangle?
Correct - what you see is all that you get! This could be any type of triangle, and each internal line could join anywhere along the side.
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Post by bomtombadil on Apr 14, 2023 17:51:04 GMT
The missing area is what has been come to be known as "The Bermuda Quadrangle". Solved!
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Post by tickingmask on Apr 14, 2023 18:16:08 GMT
The missing area is what has been come to be known as "The Bermuda Quadrangle". Solved! Ah, yes, of course, but how big is it!
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Post by bomtombadil on Apr 14, 2023 18:36:32 GMT
The missing area is what has been come to be known as "The Bermuda Quadrangle". Solved! Ah, yes, of course, but how big is it! Nobody knows because the boundaries keep shifting since they are always phasing in and out of the space-time continuum, all haphazard like. BTW, is your avatar of an Autobot that transforms into Alice Cooper?
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Post by Flying Monkeys on Apr 16, 2023 6:54:15 GMT
Back by popular demand! Sorry the image is a bit small. Can we assume that the two internal lines intersect the external lines at right angles?
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Post by tickingmask on Apr 16, 2023 9:05:00 GMT
Can we assume that the two internal lines intersect the external lines at right angles? No!!! Absolutely not!
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Post by Flying Monkeys on Apr 16, 2023 9:08:02 GMT
Can we assume that the two internal lines intersect the external lines at right angles? No!!! Absolutely not! Looks like it's drawn that way. Are you sure....?
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Post by tickingmask on Apr 16, 2023 12:17:30 GMT
No!!! Absolutely not! Looks like it's drawn that way. Are you sure....? 'Fraid so. You don't need to work out any angles in order to work out the missing area in any case, so I suspect that they don't have to be fixed in the first place (i.e. you could change the internal angles of your triangle and still construct your two internal lines to give you the same areas).
(Edit) {Heres a hint if anybody wants it.} The simplest way to determine the area of an irregular quadrilateral is to split it into two triangles and work out the area of each.
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Post by Jep Gambardella on Apr 16, 2023 15:16:54 GMT
No!!! Absolutely not! [img alt=" " src="http://storage.proboards.com/6870873/images/FySwlyxIVZHczdwVyYqH.gif" class="smile"] Looks like it's drawn that way. Are you sure....? The one on the left doesn't look like a right angle...
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Post by Flying Monkeys on Apr 16, 2023 15:22:51 GMT
Looks like it's drawn that way. Are you sure....? The one on the left doesn't look like a right angle... And if it's not a right angle, it's a wrong angle.
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Post by mowlick on Apr 19, 2023 15:16:42 GMT
Back by popular demand! Sorry the image is a bit small. ? = 39/5
That was fun.
Do you have any more ?
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Post by tickingmask on Apr 19, 2023 18:08:51 GMT
? = 39/5 That was fun. Do you have any more ?
You are right - congratulations! - but would you care to explain how you did it? I stumbled across another which I might put up here, I'll see if I can find it. It's one of those ones that you either see or you don't (and I didn't ) but is fairly easy to explain once you do.
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Post by mowlick on Apr 19, 2023 20:32:51 GMT
? = 39/5 That was fun. Do you have any more ?
You are right - congratulations! - but would you care to explain how you did it? I stumbled across another which I might put up here, I'll see if I can find it. It's one of those ones that you either see or you don't (and I didn't ) but is fairly easy to explain once you do. I can explain, but not for a few hours because it requires a sketch and I have no idea how to upload one until my son comes home
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