|
Post by iamnotarobot on Jul 24, 2019 18:42:51 GMT
My rivers and streams always go from left to right btw. So does that one. OK I stand corrected. I had the boat going left to right, not the stream. The way you did it was still backwards no matter what way the stream is going.
|
|
|
Post by Flying Monkeys on Jul 24, 2019 18:48:58 GMT
OK I stand corrected. I had the boat going left to right, not the stream. Huh? If you had the boat going left to right, then you had the stream going right to left which contradicts what you said about how you draw rivers...? What do you mean backwards? Boat starts at A, rows to B, then to C. The order of the letters matches the order in which the events occur. How can that possibly be backwards? Makes perfect sense.
|
|
|
Post by iamnotarobot on Jul 24, 2019 18:53:30 GMT
OK I stand corrected. I had the boat going left to right, not the stream. Huh? If you had the boat going left to right, then you had the stream going right to left which contradicts what you said about how you draw rivers...? What do you mean backwards? Boat starts at A, rows to B, then to C. The order of the letters matches the order in which the events occur. How can that possibly be backwards? Makes perfect sense. Do you read Hebrew all the time? That's the only way to explain how backwards you are. I had the object of the problem going left to right. That is the most logical and correct way. You had the boat going in the wrong direction.
|
|
|
Post by iamnotarobot on Aug 15, 2019 17:03:03 GMT
OK I stand corrected. I had the boat going left to right, not the stream. Huh? If you had the boat going left to right, then you had the stream going right to left which contradicts what you said about how you draw rivers...? What do you mean backwards? Boat starts at A, rows to B, then to C. The order of the letters matches the order in which the events occur. How can that possibly be backwards? Makes perfect sense. Here's a straightforward math problem. Factor x^4+y^4+z^4 - 2(x^2 y^2) - 2(x^2 z^2) - 2(y^2 z^2) I will give you the answer (x+y+z) (x-y+z) (x+y-z) (x-y-z) Of course the challenge how to arrive at that answer. It took me many hours to solve this one.
|
|
|
Post by Flying Monkeys on Aug 15, 2019 18:26:06 GMT
iamnotarobot, I'll try it tomorrow. My first thought is to replace x+y with 'a' and x-y with 'b', and see what drops out.
|
|
|
Post by iamnotarobot on Aug 15, 2019 18:34:44 GMT
iamnotarobot , I'll try it tomorrow. My first thought is to replace x+y with 'a' and x-y with 'b', and see what drops out. There is no x+y or x-y in the equation.
|
|
|
Post by iamnotarobot on Aug 15, 2019 18:53:00 GMT
iamnotarobot , I'll try it tomorrow. My first thought is to replace x+y with 'a' and x-y with 'b', and see what drops out. Here it is exactly as it appears in a Soviet era Russian math book I bought in the 80s. I changed the variables in the earlier post to what we are more familiar with. It takes some ingenuity to solve. i.postimg.cc/R0GC0qXk/maths.jpg
|
|
|
Post by iamnotarobot on Aug 17, 2019 20:31:56 GMT
iamnotarobot , I'll try it tomorrow. My first thought is to replace x+y with 'a' and x-y with 'b', and see what drops out. I was very disappointed with myself yesterday when I remembered that when I tried to solve that 2 or 3 yrs ago I was stumped and had to seek out the answer at Yahoo Answers. Someone there named "Math Mom" solved it. She seems to be a math whiz.
|
|